jazlynebermudez
contestada

An alloy that is 30% silver is mixed with 200 g of a
10% silver alloy. How much of the 30% alloy must
be used to obtain an alloy that is 24% silver?
show work plz

Respuesta :

Novachrono12

Answer:

The answer is [tex]466\frac{2}{3}\,g[/tex]

Step-by-step explanation:

Let,

Amount of alloy with 30% silver = x g

Given,

Amount of alloy with 10% silver = 200 g

So, Total Amount of alloy with 24% silver = (x+200) g

Now,

[tex]x*0.30+200*0.10=(x+200)*0.24\\=>0.30x+20=0.24x+48\\=>0.06x=28\\x=466\frac{2}{3}\,g=466.67\,g[/tex]

Hope you have understood this....

pls mark my answer as the brainliest

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