Respuesta :

Answer:

[tex]q^{-30}[/tex]

Step-by-step explanation:

[tex](p^{2}q^{5})^{-4}\cdot(p^{-4}q^{5})^{-2}\\=p^{-8}q^{-20}\cdot p^{8}q^{-10}\\=p^{-8+8}\cdot q^{-20+-10}\\=q^{-30}\\[/tex]

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