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The moon Phobos orbits Mars
(m = 6.42 x 10^23 kg) at a distance of
9.38 x 10^6 m. What is the Phobos'
orbital velocity?
[?] m/s

Respuesta :

Explanation:

For a circular orbit v= [tex]\sqrt{\frac{G.m}{r} }[/tex] with G = 6.6742 × [tex]10^{-11}[/tex]

Given m = 6.42 x 10^23 kg and  r=9.38 x 10^6 m

=> v = 2137.3 m/s

I hope this is the correct way to solve

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