Jesse travels 3.0 meters east and then turns and travels 4.0 meters north. The trip requires 35 seconds. What is his velocity?

Respuesta :

Using Pythagorean triplet

[tex]\\ \sf\longmapsto AB^2=AC^2-BC^2[/tex]

[tex]\\ \sf\longmapsto AB^2=4^2-3^2[/tex]

[tex]\\ \sf\longmapsto AB^2=16-9[/tex]

[tex]\\ \sf\longmapsto AB^2=7[/tex]

[tex]\\ \sf\longmapsto AB=\sqrt{7}[/tex]

  • Now time=35

[tex]\\ \sf\longmapsto Velocity=\dfrac{Displacement}{Time}[/tex]

[tex]\\ \sf\longmapsto Velocity=\dfrac{\sqrt{7}}{35}[/tex]

[tex]\\ \sf\longmapsto Velocity=\dfrac{2.6}{35}[/tex]

[tex]\\ \sf\longmapsto Velocity=0.07m/s[/tex]

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