factorization please help

Answer:
(p - 3q)/ 5p
Step-by-step explanation:
p^2 - 7pq + 12 q^2
= (p - 3q)(p - 4q)
and
5p^2 - 20 pq = 5p(p - 4q)
The p - 4q is common to both expressions so the answer is
(p - 3q)/ 5p.
Answer:
[tex]\frac{p-3q}{5p}[/tex]
Step-by-step explanation:
Given
[tex]\frac{p^2-7pq+12q^2}{5p^2-20pq}[/tex] ← factorise numerator and denominator
= [tex]\frac{(p-4q)(p-3q)}{5p(p-4q)}[/tex] ← cancel (p - 4q) on numerator/ denominator
= [tex]\frac{p-3q}{5p}[/tex]