Answer:
Step-by-step explanation:
To answer this we need only know that negative parabolas are upside down, so by definition, it has a max point at the vertex. To find the vertex (h, k), the easy way to do this is to fill in the following expressions for h and k and solve:
[tex]h=\frac{-b}{2a}[/tex] and [tex]k=c-\frac{b^2}{4a}[/tex] (These are derived from the quadratic formula). Filling in knowing our a = -1, b = -7, c = 12:
[tex]h=\frac{-(-7)}{2(-1)}=\frac{7}{-2}=-\frac{7}{2}[/tex] and
[tex]k=12-\frac{(-7)^2}{4(-1)}=12-(\frac{49}{-4})=12+\frac{49}{4}=\frac{97}{4}[/tex] so the vertex (aka max height occurs at [tex](-\frac{7}{2},\frac{97}{4})[/tex]. Depending upon what is meant by stating the max value, we may only need to state the k value (which is the same as the y coordinate, which is an up or down thing as opposed to the x value which is a side to side thing). The domain is all real numbers, as is the case for all x-squared parabolas, and the range is
R = {y | y ≤ 97/4}
I can't see your choices so match them up from these answers to the ones in the list of choices.
