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Answer:
B.
[tex]{ \tt{f(x) = \sqrt[3]{x + 11} }}[/tex]
let the inverse of f(x) be m:
[tex]{ \tt{m = \sqrt[3]{x + 11} }} \\ { \tt{ {m}^{3} = x + 11}} \\ { \tt{ {m}^{3} - 11 = x}} \\ { \tt{ {f}^{ - 1}(x) = {m}^{3} - 11 }}[/tex]
substitute for x in place of m:
[tex]{ \bf{f {}^{ - 1}(x) = {x}^{3} - 11 }}[/tex]