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2.13 LAB: Branches: Leap Year
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the
difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The
requirements for a given year to be a leap year are:
1) The year must be divisible by 4
2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400
Some example leap years are 1600, 1712 and 2016.
Write a program that takes in a year and determines whether that year is a leap year.
Ex If the input is
1712
the output is
1712 13 leap year.
Ex If the nouts
1913
the outoutis
1913 not leap year.
Written is Coral Language

Respuesta :

RemielUri

Answer:

integer userInput

userInput = Get next input

if userInput % 400 == 0

  Put userInput to output

  Put " is a leap year" to output

else

  if userInput % 4 == 0

     Put userInput to output

     Put " is a leap year" to output

  else

     Put userInput to output

     Put " is not a leap year" to output

Explanation:

I don't know what is so special about Coral but here we go. I couldn't find and IDE that supported Coral so I just used their Coral simulator on their website. The first if statement on line 5 determines if the number is divisible by 400. If so, the leap year is on a century year e.g 1900 1800. If not, the else statement will be executed and the second if statement will execute. If the number is divisible by 4, it is a leap year. If not, the else statement gets executed in which case the number was not a century leap year or a leap year. After that the program terminates.

Hope this helped :)  If it didn't let me know and I do my best to find out what went wrong.

Have a good day :)

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