Answer:
see explanation
Step-by-step explanation:
1
(a)
Calculate slope m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ = (8, 3) and (x₂, y₂ ) = (10, 7)
m = [tex]\frac{7-3}{10-8}[/tex] = [tex]\frac{4}{2}[/tex] = 2
(b)
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{2}[/tex]
(c)
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - [tex]\frac{1}{2}[/tex] , then
y = - [tex]\frac{1}{2}[/tex] x + c ← is the partial equation
To find c substitute (8, 3) into the partial equation
3 = - 4 + c ⇒ c = 3 + 4 = 7
y = - [tex]\frac{1}{2}[/tex] x + 7 ← equation of perpendicular line
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2
(a)
with (x₁, y₁ ) = (3, 5) and (x₂, y₂ ) = (4, 4)
m = [tex]\frac{4-5}{4-3}[/tex] = [tex]\frac{-1}{1}[/tex] = - 1
(b)
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{-1}[/tex] = 1
(c)
y = x + c ← is the partial equation
To find c substitute (3, 5) into the partial equation
5 = 3 + c ⇒ c = 5 - 3 = 2
y = x + 2 ← equation of perpendicular line
