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A tube with a membrane covering the bottom is placed in a beaker. The membrane allows water to flow through but not salt or glucose. The tube contains an aqueous solution with 4% salt and 20% glucose and the beaker contains an aqueous solution with 12% salt and 6% glucose. How could you describe the solution in the beaker compared to the solution in the tube

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rococo908

Answer:

The solution in the tube is hypertonic to the solution in the beaker.

Explanation:

To compare the solutions, find the total amount of solutes in both the tube and beaker.

The tube has 4% salt and 20% glucose, so it has 24% solute.

The beaker has 12% salt and 6% glucose, so it has 18% solute.

Since 24 is larger than 18, this means the tube has more solute.

Since the tube has more solute and less water compared to the beaker, it is hypertonic to the beaker.

So, the answer is that the solution in the tube is hypertonic to the solution in the beaker.

marianaegarciaperedo

Solutions are hypertonic or hypotonic to other solutions according to their solute concentration grade. In the exposed example, the beaker aqueous solution is hypotonic to the tube solution, meaning it is less concentrated.

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Available data:

  • The membrane allows water to flow through but not salt or glucose
  • The tube contains an aqueous solution with 4% salt and 20% glucose
  • The beaker contains an aqueous solution with 12% salt and 6% glucose

We need to describe and compare solutions.

To do it, first, we will review some theoretical framework.

When talking about solutions in compartison with the cell content, we can classify them as follows,

• HYPERTONIC ⇒ A hypertonic solution has a higher concentration of solute than the cell. This means that in the cell interior, the solute concentration is lower than in the solution itself.

• ISOTONIC ⇒ The solute concentration is the same inside the cell and outside.

• HYPOTONIC ⇒ A hypotonic solution has a lower concentration of solute than the cell. This means that in the cell interior, the solute concentration is higher than in the solution itself.  

When a cell is in a hypotonic solution, through osmosis, water moves toward the cell.  

Osmosis is the phenomenon that occurs when two dilutions of different concentrations -in this example, the interior of the tube and the beaker- are separated by a semipermeable membrane.

The membrane allows the pass of water but not solute. Hence, water can move from the most diluted side to the less diluted one.  

What we need to consider is

• When a cell with semipermeable membrane is placed in a hypotonic solution, water enters the cell.

• When a cell with semipermeable membrane is placed in an isotonic solution, there is no water movement.

• When a cell with semipermeable membrane is placed in a hypertonic solution, water gets out of the cell.

In simple words, in the proposed experiment, glucose and salt -solutes- can not cross the membrane, but water can. The tube represents a cell. So,

  • The tube has 4% salt and the beaker 12 % salt
  • The tube has 20% glucose and the beaker 6% glucose.

To make the analysis easier, we can add the concentration percentages of glucose and salt at each side of the membrane, and then compare them.

  • The tube contains an aqueous solution with 24% solute (4% salt + 20% glucose)
  • The beacker contains an aqueous solution with 18% solute (12% salt + 6% glucose)

We can see that the concentration of solute is higher in the interior of the tube than in the beaker. This difference suggests that water will move forward to the tube interior.

According to this analysis, we can say that

  • The tube aqueous solution is hypertonic to the beaker solution → More concentrated

  • The beaker aqueous solution is hypotonic to the tube solution → Less concentrated

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You can learn more about hypertonic and hypotonic solutions at

https://brainly.com/question/13210811?referrer=searchResults

https://brainly.com/question/18806725?referrer=searchResults

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