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A box with a mass of 5 kg accelerates its speed in a straight line, increasing it from 5 m/s to 8 m/s, due to the application of an external force acting for a duration of 2.0 s. Calculate the average strength of this force.

Respuesta :

Explanation:

acceleration a = v-v0/ t = ∆V/∆t

first we must calculate F = M.A

The average strength of this force will be 7.5 N

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Force,F = ?

Mass,m = 5 kg

Initial velocity,u=5 m/sec

Final velocity,v==8 m/sec

Time period,t=2.0 sec

The average strength of this force will be;

F=m[(v-u)/t]

F= 5 kg × [(8 m/sec -5 m/sec)/2.0 sec]] m/s²

F= 7.5 N

Hence the average strength of this force will be 7.5 N

To learn more about the force refer to the link;

https://brainly.com/question/26115859

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