find the x – intercepts of the graph of the function f(x) = x2 – 2x + 1

A) (1,0)
B) (-1,0)
C) (0,-1)
D) (0,1)

PLEASE HELP ME ITS URGENT , WILL MARK AS BRAINLIEST!!!

Respuesta :

Answer:

[tex]\boxed{\sf A) ( 1,0) }[/tex]

Step-by-step explanation:

A quadratic function is given to us and we need to find the x Intercept of the graph of the given function . The function is ,

[tex]\sf \implies f(x) = x^2 -2x + 1 [/tex]

For finding the x intercept , equate the given function with 0, we have ;

[tex]\sf \implies x^2 -2x + 1 = 0 [/tex]

Split the middle term ,

[tex]\sf \implies x^2-x-x+1=0[/tex]

Take out common terms ,

[tex]\sf \implies x( x -1) -1( x -1) = 0[/tex]

Take out (x - 1 )as common ,

[tex]\sf \implies (x - 1 )(x-1) = 0[/tex]

Equate with 0 ,

[tex]\sf \implies x = 1,1 [/tex]

Therefore the root of the function is 1. Hence the x Intercept is (1,0)

Hence the x Intercept is (1,0) .

Step-by-step explanation:

x² - 2x + 1 = 0

x² - (x + x) + 1 = 0

x² - x - x + 1 = 0

x(x - 1) - 1(x - 1) = 0

(x - 1)(x - 1) = 0

x = 1

Hence,

Option A

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