Answer:
C. As x approaches positive infinity, g(x) approaches positive infinity.
Step-by-step explanation:
We are given the following function:
[tex]g(x) = \frac{|x-3|}{2} - 7[/tex]
End behavior:
Limit of g(x) as x goes to negative and positive infinity.
Negative infinity:
[tex]\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} \frac{|x-3|}{2} - 7 = \frac{|-\infty-3|}{2} - 7 = |-\infty| = \infty[/tex]
Positive infinity:
[tex]\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{|x-3|}{2} - 7 = \frac{|\infty-3|}{2} - 7 = |\infty| = \infty[/tex]
So in both cases, it approaches positive infinity, and so the correct option is c.
