Answer:
C. 5
Step-by-step explanation:
The given data can be presented as follows;
[tex]\begin{array}{ccc}x&&y\\2&\leftrightarrow &1\\3&\leftrightarrow &4\\4&\leftrightarrow &6\\5&\leftrightarrow &7\\6&\leftrightarrow &6\\7&\leftrightarrow &3\\8&\leftrightarrow &2\\9&\leftrightarrow &1\\10&\leftrightarrow &1\end{array}[/tex]
We find the sum of the data points as follows;
n = 1 + 4 + 6 + 7 + 6 + 3 + 2 + 1 + 1 = 31
The median will be located in the (n + 1)/2 th data point
Therefore the median is the (31 + 1)/2 = 16th data point
The sum of the first three bars on the histogram = 11
The sum of the first four bars on the histogram = 18
Therefore, the 16th data point is located in the fourth bar which has x value of 5
The median is therefore, C. 5
