Answer:
3.98×10⁻¹⁹ J
Explanation:
Applying,
E = hf................. Equation 1
Where E = energy of the photon, h = planck's constant, f = frequency of the photon
From the question,
Given: f = 6.00×10¹⁴ Hz
Constant: h = 6.626×10⁻³⁴J.s
Substitute these values into equation 1
E = (6.00×10¹⁴)(6.626×10⁻³⁴)
E = 39.756×10⁻²⁰
E = 3.98×10⁻¹⁹ J
Hence the energy of the photon in joules is 3.98×10⁻¹⁹ J
