Answer:
The quadrilateral is a parallelogram
Step-by-step explanation:
If you plot the points on the graph it resembles the shape of a parallelogram. It prove this you need to check if the lengths are correct. The slope between point A and point B is 1/3 and the slope between point C and point D is also 1.3. The slope between point B and D is 1/2 and the slope between point A and point C is also 1/2
hope this helps
The quadrilateral is a parallelogram from the graph and the coordinates formed are parallel and the opposite sides have equal length.
A parallelogram is a quadrilateral whose opposite sides are parallel and equal in length. The opposite angles of a parallelogram are equal. The diagonals of a parallelogram bisect each other.
For the given situation,
The coordinates are A(2, 3) B(-1, 4) C(0, 2) D(-3, 3).
The graph below shows these points on the coordinates and the points ABDC forms the parallelogram.
This can be proved by finding the distance between these points.
The formula of distance between two points is
[tex]AB=\sqrt{(x2-x1)^{2}+ (y2-y1)^{2}}[/tex]
Distance AB is
⇒ [tex]AB=\sqrt{(-1-2)^{2}+ (4-3)^{2}}[/tex]
⇒ [tex]AB=\sqrt{(-3)^{2}+ (1)^{2}}[/tex]
⇒ [tex]AB=\sqrt{9+ 1}[/tex]
⇒ [tex]AB=\sqrt{10}[/tex]
Distance BD is
⇒ [tex]BD=\sqrt{(-3+1)^{2}+ (3-4)^{2}}[/tex]
⇒ [tex]BD=\sqrt{(-2)^{2}+ (-1)^{2}}[/tex]
⇒ [tex]BD=\sqrt{4+ 1}[/tex]
⇒ [tex]BD=\sqrt{5}[/tex]
Distance DC is
⇒ [tex]DC=\sqrt{(0+3)^{2}+ (3-2)^{2}}[/tex]
⇒ [tex]DC=\sqrt{(3)^{2}+ (1)^{2}}[/tex]
⇒ [tex]DC=\sqrt{9+ 1}[/tex]
⇒ [tex]DC=\sqrt{10}[/tex]
Distance CA is
⇒ [tex]CA=\sqrt{(2-0)^{2}+ (3-2)^{2}}[/tex]
⇒ [tex]CA=\sqrt{(2)^{2}+ (1)^{2}}[/tex]
⇒ [tex]CA=\sqrt{4+ 1}[/tex]
⇒ [tex]CA=\sqrt{5}[/tex]
Thus the lengths of the opposite sides are equal, the given points forms the parallelogram.
Hence we can conclude that the quadrilateral is a parallelogram from the graph and the coordinates formed are parallel and the opposite sides have equal length.
Learn more about parallelogram here
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