Answer:
[tex]T_F=77.4\°C[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:
[tex]Q_1=-Q_2[/tex]
In terms of mass, specific heat and temperature change is:
[tex]m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)[/tex]
Now, solve for the final temperature, as follows:
[tex]T_F=\frac{m_1C_1T_1+m_2C_2T_2}{m_1C_1+m_2C_2}[/tex]
Then, plug in the masses, specific heat and temperatures to obtain:
[tex]T_F=\frac{760g*0.87\frac{J}{g\°C} *52.2\°C+70.7g*3.071\frac{J}{g\°C}*154\°C}{760g*0.87\frac{J}{g\°C} +70.7g*3.071\frac{J}{g\°C}} \\\\T_F=77.4\°C[/tex]
Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.
Regards!
