Answer:
E= 80.71 MegaN/C
Explanation:
The radius of the disk is 35.0 cm.
The charge density is 7.9 x 10^-3 C/m^2
The distance from the center of the disk is 50.0 cm
The electric field is given by the expression as shown below:
[tex]E=2 \pi k_{e} \sigma\left[1-\frac{x}{\left(R^{2}+x^{2}\right)^{1 / 2}}\right][/tex]
Plugging the values in the above expression,
E = (2 *3.14 * 7.9 *10^-3 * 9 *10^9) *(1-(0.5/(sqrt(0.5^2+ 0.35^2)))
E= 80.71 MegaN/C
