Rivkah0 Rivkah0

18-06-2021
Physics

contestada

An object of mass 3kg was released from 40m above the ground. Using the conservation of energy, determine the velocity of the object right before hitting the ground.

Respuesta :

kushm6652 kushm6652

02-07-2021

Answer:

v=28m/s

Explanation:

Conservation of Energy

Ei=Ef

mgh= 1/2mv^2

9.8*40*2= v^2

784= v^2

v= 28m/s

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