Answer:
See explanation
Explanation:
Number of moles of Copper sulphate = 0.18 M × 6.5/1000= 1.17 × 10^-3 moles of CuSO4
From;
number of moles = mass/molar mass
Molar mass of copper II sulphate = 160g/mol
1.17 × 10^-3 moles = mass/160g/mol
Mass = 1.17 × 10^-3 moles ×160
Mass = 0.187 g
If 1 mole contains 6.02 × 10^23 molecules
1.17 × 10^-3 moles contains 1.17 × 10^-3 moles × 6.02 × 10^23/1 = 7 × 10^20 molecules
From;
C1 V1=C2 V2
0.18 × 6.5 =C2 × 10.5
C2 = 0.18 × 6.5/10.5
C2=0.11 M
CuSO4(aq) + 2NaOH(aq) ----> Cu(OH)2(s) + Na2SO4(aq)
1 mole of CuSO4 yields 1 mole of Cu(OH)2
1.17 × 10^-3 moles of CuSO4 yields 1.17 × 10^-3 moles of Cu(OH)2
Mass of Cu(OH)2 = 1.17 × 10^-3 moles × 98g/mol= 0.11g of Cu(OH)2
