A field is a rectangle with a perimeter of 1100 feet. The length is 300 feet more than the width. Find the width and length of the rectangular field

Respuesta :

Answer:

Step-by-step explanation:

perimeter of rectangle = 1100

let breadth be x

length = 300 + x

perimeter of rectangle = 2(l + b)

1100 = 2(300 + x + x)

1100 = 2(300 + 2x)

1100 = 600 + 4x

1100 - 600 = 4x

500 = 4x

500/4 = x

125 = x

therefore breadth is 125 feet

length = 300 + 125

=425 feet

Answer:

The rectangular field is 425 feet by 125 feet.

Step-by-step explanation:

Let w represent the width of the rectangular field.

Since the length is 300 feet more than the width, the length can be modeled by the expression (w + 300).

The perimeter of a rectangle is given by the formula:

[tex]P=2(w+\ell)[/tex]

Where P is the perimeter and w and l are the width and length, respectively.

We are given that the perimeter is 1,100 feet. Substitute:

[tex]1100=2(w+\ell)[/tex]

Divide both sides by two:

[tex]550=w+\ell[/tex]

We know that l = (w + 300). So:

[tex]550=w+(w+300)[/tex]

Simplify:

[tex]2w=250[/tex]

Divide both sides by two. So, the width is:

[tex]w=125\text{ feet}[/tex]

Since the length is 300 feet more than the width, that means the length is 425 feet.

The rectangular field is 425 feet by 125 feet.

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE