Answer:
x = [tex]\sqrt5[/tex]
Step-by-step explanation:
Using Pythagoras theorem,
Square of longer side = Sum of square of other sides .
Therefore,
[tex](\sqrt{11})^2 = x^2 + (\sqrt{6})^2\\\\11 = x^2 + 6\\\\11 - 6 = x^2\\\\5 = x^2\\\\x = \sqrt 5[/tex]
