Over ten years, the population of fish in a lake increases by 3%. After the increase, there are 10,094 fish. Which expressions are equivalent to the number of fish ten years before? Select all that apply.

Respuesta :

Answer:

9800 Fish

Step-by-step explanation:

According to The question,

  • Given, the population of fish in a lake increases by 3% for over ten years, after the increase there are 10094 fish .

The number of fish ten years before is [tex]10094 * \frac{100}{103}[/tex] ⇔ 9800 fish

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