Answer:
36.30 M
Explanation:
Given that:
Molar mass of ammonium sulfite (NH₄)₂ SO₃ = 100.154 g/mol
Volume = 3.3 mL
to liters, we have: (3.3/1000)L
= 0.0033 L
mass = 12 grams
The concentration of the solution = [tex]\dfrac{12 \ g}{ 100 .154 \ g/mol}\times \dfrac{1}{0.0033 \ L}[/tex]
= 36.30 M
