If line ab is tangent to circle c , find AC?
Can anyone help?

Answer:
Step-by-step explanation:
If AB is tangent to the circle, the AB makes a right angle with the radius BC. That means that triangle ABC is a right triangle and we need Pythagorean's Theorem to find the missing side which is the hypotenuse.
[tex]AC^2=AB^2+BC^2[/tex] and filling in:
[tex]AC^2=14^2+9^2[/tex] and
[tex]AC^2=196+81[/tex] and
[tex]AC^2=277[/tex] so
[tex]AC=\sqrt{277}[/tex] ≈ 16.64
AC = 16.64
"It states that a line is a tangent to a circle if and only if the line is perpendicular to the radius drawn to the point of tangency."
From given diagram,
tangent AB = 14 units
radius BC = 9 units
Using tangent theorem,
AB is perpendicular to BC.
This means ΔABC is right triangle with ∠B = 90°
Using Pythagoras theorem,
[tex]AC^2=AB^2+BC^2[/tex]
⇒ [tex]AC^2=14^{2}+9^{2}[/tex]
⇒ [tex]AC^2=196+81[/tex]
⇒ [tex]AC^2=277[/tex]
⇒ [tex]AC=\sqrt{277}[/tex]
⇒ [tex]AC=16.64[/tex]
Therefore, AC = 16.64
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