Answer:
8761.5 N
Explanation: Given that a car with a mass of 1,120.0 kg accelerates from 0 to 80.0 km/h in 10.0 s. The driver applies the brakes when the car is moving at 80.0 km/h, and the car comes to rest after traveling 44.0 m. What is the net force (in N) on the car during its deceleration
Mass m = 1120kg
First change km/h to m/s
(80 × 1000) ÷ 3600
Velocity = 22.2 m/s
Acceleration = ( 22.2 - 0 ) ÷ 10
Acceleration = 2.2 m/s^2
Force F1 = mass × acceleration
Substitutes all the parameters into the formula
F1 = 1120 × 2.2
F1 = 2489 N
For the car to come to rest, it will be decelerating.
Using 3rd law of motion
V^2 = U^2 + 2as
V = 0 since it is coming to rest.
Substitute all the parameters into the formula
0 = 22.2^2 - 2 × a × 44
88a = 492.84
a = 492.84/88
a = 5.6 m/s^2
The force F2 = 1120 × 5.6
F2 = 6272.5N
Net force = 6272.5 + 2489
Net force = 8761.5 N
Therefore, the net force is 8761.5 N
