Answer:
a) - 7.40 * 10^6 Nm^2/C^2
b) More lines enter than leave the surface
Explanation:
a)
As per the Gauss Law
ε * Intg E.dS = q
E.dS = flux over the whole hull of the submarine
ε = permittivity of vacuum
flux = Σ (charges)/permittivity of vacuum = ( 6.95 + -9 + 27 + -90.5 )*10^-6/8.85 x 10^-12 =
= -0.00006555 /(8.85 x 10^-12)
= - 7.40 * 10^6 Nm^2/C^2
b) The net electric flux is negative, more lines enter than leave the surface.
