Explanation:
Given:
l = 55.0 cm = 0.550 m
T = (130 s)/100 = 1.30 s
g = ?
The period of a pendulum is given by
[tex]T=2 \pi \sqrt{ \dfrac{l}{g}}[/tex]
Solving for T, we get
[tex]\dfrac{T^2}{4 \pi^2}=\dfrac{l}{g}[/tex]
Solving for g, we get
[tex]g=\dfrac{4 \pi^2l}{T^2}=\dfrac{4 \pi^2(0.550 m)}{(1.30\:s)^2}=12.8\:\dfrac{m}{s^2}[/tex]
