Answer:
C.
[tex]x=\frac{-7±\sqrt{5 } }{2}[/tex]
Step-by-step explanation:
4x² + 28x + 49 = 5
4x² + 28x + 49 - 5 = 0
4x² + 28x + 44 = 0
4(x² + 7x + 11) = 0
4(x² + 7x + 11) ÷ 4 = 0 ÷ 4
x² + 7x + 11 = 0
[tex]x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}[/tex]
Ignore the A before the ±. It wouldn't let me type it correctly.
a = 1
b = 7
c = 11
[tex]x=\frac{-7±\sqrt{7^{2}-4((1)(11)) } }{2(1)}[/tex]
[tex]x=\frac{-7±\sqrt{49-4((1)(11)) } }{2(1)}[/tex]
[tex]x=\frac{-7±\sqrt{49-44 } }{2(1)}[/tex]
[tex]x=\frac{-7±\sqrt{5 } }{2(1)}[/tex]
[tex]x=\frac{-7±\sqrt{5 } }{2}[/tex]
