Answer:
[tex]x=-1+\sqrt{6 }[/tex]
[tex]x=-1-\sqrt{6 }[/tex]
Step-by-step explanation:
[tex]x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}[/tex]
Ignore the A before the ±. It wouldn't let me type it correctly.
x² + 2x - 5 = 0
a = 1
b = 2
c = - 5
[tex]x=\frac{-2±\sqrt{2^{2}-4((1)(-5)) } }{2(1)}[/tex]
[tex]x=\frac{-2±\sqrt{4-4((1)(-5)) } }{2(1)}[/tex]
[tex]x=\frac{-2±\sqrt{4+20 } }{2(1)}[/tex]
[tex]x=\frac{-2±\sqrt{24 } }{2}[/tex]
[tex]x=\frac{-2±\sqrt{(2)(12) } }{2}[/tex]
[tex]x=\frac{-2±\sqrt{(2)(2)(6) } }{2}[/tex]
[tex]x=\frac{-2±\sqrt{(2)(2)(2)(3) } }{2}[/tex]
[tex]x=\frac{-2±(\sqrt{2} )(\sqrt{2})(\sqrt{(2)(3) )} }{2}[/tex]
[tex]x=\frac{-2±2\sqrt{6 } }{2}[/tex]
Two separate equations
[tex]x=\frac{-2+2\sqrt{6 } }{2}[/tex]
[tex]x=\frac{-2-2\sqrt{6 } }{2}[/tex]
[tex]x=-1+\sqrt{6 }[/tex]
[tex]x=-1-\sqrt{6 }[/tex]
