Help Pls. Find the radius of Circle Q.

The radius of the given circle is 13 unit.
The chord of a circle can be defined as the line segment joining any two points on the circumference of the circle.
A radius is a measure of distance from the center of any circular object to its outermost edge or boundary.
Pythagoras theorem states that "the square on the hypotenuse of a right-angled triangle is equal in area to the sum of the squares on the other two sides".
According to the given question
We have a circle with center Q and two chords AD and BC.
And, AD = 4x + 4 and BC = 6x -6
Since, both the chords are at the same distance from the center of the circle, so their lengths will same.
⇒ AD = BC
⇒ 4x + 4 = 6x -6
⇒ 4 + 6 = 6x -4x
⇒ 10 = 2x
⇒ x = 5
Therefore,
AD = 4x + 4 = 4(5) + 4 = 20 +4 =24
and, BC = 6x - 6 = 6(5) - 6 = 30 -6 = 24
Also, AP = AD/2 = 24/2 = 12
Now, in right angle triangle QPA we have
[tex]AQ^{2} =QP^{2} +AP^{2}[/tex] ( By Pythagoras theorem)
⇒ [tex]AQ^{2} = 5^{2} +12^{2}[/tex]
⇒[tex]AQ^{2} = 25 + 144[/tex]
⇒[tex]AQ^{2} = 169[/tex]
⇒[tex]AQ =\sqrt{169}[/tex]
⇒ AQ = 13
Hence, the radius of the given circle is 13 unit.
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