Answer:
1.21 mol KClO₃
General Formulas and Concepts:
Atomic Structure
- Reading a Periodic Table
- Moles
- Mole Ratio
Stoichiometry
- Analyzing reactions rxn
- Using Dimensional Analysis
Explanation:
Step 1: Define
Identify variables
[rxn] 2KClO₃ → 2KCl + 3O₂
[Given] 58.3 g O₂
[Solve] mol KClO₃
Step 2: Identify Conversions
[rxn] 2 mol KClO₃ → 3 mol O₂
[PT] Molar Mass of O: 16.00 g/mol
Molar Mass of O₂: 2(16.00) = 32.00 g/mol
Step 3: Convert
- [DA] Set up: [tex]\displaystyle 58.3 \ g \ O_2(\frac{1 \ mol \ O_2}{32.00 \ g \ O_2})(\frac{2 \ mol \ KClO_3}{3 \ mol \ O_2})[/tex]
- [DA] Divide/Multiply [Cancel out units]: [tex]\displaystyle 1.21458 \ mol \ KClO_3[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
1.21458 mol KClO₃ ≈ 1.21 mol KClO₃
