Given the following information, calculate the density in g/mL of an irregular solid.

Mass of weighing vessel 1.005g
Mass of solid + weighing vessel 9.441g
Volume of liquid in graduated cylinder 3.45 mL
Volume of liquid in graduated cylinder + volume of solid 5.45 mL

Respuesta :

Answer:

4.22 g/mL

Explanation:

First we calculate the mass of the solid via mass difference:

  • Mass of solid = 9.441 g - 1.005 g = 8.436 g

Then we calculate the volume of the solid, once again by difference:

  • Volume of solid = 5.45 mL - 3.45 mL = 2.00 mL

Finally we calculate the density in g/mL:

  • Density = 8.436 g / 2.00 mL = 4.22 g/mL

The density of an irregular solid will be "4.96 g/mL".

According to the question,

→ The Mass of solid will be:

= [tex][(Mass \ of \ solid+ Weighing \ vessel)-(Mass \ of \ weighing)][/tex]

By substituting the values, we get

= [tex]9.441-1.005[/tex]

= [tex]8.436 \ g[/tex]

→ The Volume of solid will be:

= [tex][(Volume \ of \ liquid \ in \ grad. \ cylinder+Solid)-(Volume \ of \ grad. \ cylinder)][/tex]

= [tex]5.15 - 3.45[/tex]

= [tex]1.70 \ mL[/tex]

hence,

→ The density of irregular solid will be:

= [tex]\frac{Mass}{Volume}[/tex]

= [tex]\frac{8.436}{1.70}[/tex]

= [tex]4.96 \ mL[/tex]

Thus the above is the correct answer.

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