Find the equation of the quadratic function determined from the graph above.
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Find the equation of the quadratic function determined from the graph above.
The vertex of the graph of the quadratic function is (2, -3). The graph passes through the point (5, 0). By replacing x and y with 5 and 0, respectively, and h and k with 2 and -3, respectively we have,
[tex]\sf\rightarrow{y=a(x-h)²+k}[/tex]
[tex]\sf\rightarrow{O=a(5-2)²-3}[/tex]
[tex]\sf\rightarrow{0=a(3)²-3}[/tex]
[tex]\sf\rightarrow{3=9a}[/tex]
[tex]\sf\rightarrow{a=\frac{1}{3}}[/tex]
[tex]\sf\rightarrow{y=\frac{1}{3}(x-2)²-3}[/tex]
or,
[tex]\sf{y=\frac{1}{3} \: x²-\frac{4}{3} \: x-\frac{5}{3}}[/tex]
#Hope it helps!
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Answer:
y = (x-2)²/3 - 3
Step-by-step explanation:
the vertex is at (2,-3), so the vertex form of the function is
y = A(x-2)²-3
where A is a constant to be found.
We see that when x=5, y=0, so substitute values to find A.
0 = A(5-2)² - 3
solve for A to get
A(3²) = 3
A = 1/3
So the equation is
y = (x-2)²/3 - 3
Check for x = -1
y = (-1-2)²/3 - 3 = 0 checks