Answer:
75 N
Explanation:
Given that,
The angle of incline of the ramp is 42°.
The gravitational force of the box, W = 112.1 N
We need to find the force of static friction on the box.
We have that the component of the gravitational force acting along the inclined plane i.e.
[tex]F=W\sin\theta\\\\F=112.1\times \sin(42)\\\\F=75\ N[/tex]
So, the force of static friction is equal to 75 N.
