An inflated balloon contains X air molecules.After some time the volume of the balloon is found to be the half at the same temperature and pressure when a few air molecules are expelled out. a)How many molecules will be there in the balloon now? b) Which is the gas law associated with this?

Respuesta :

Answer:

(a): The balloon will contain [tex]\frac{X}{2}[/tex] number of molecules now.

(b): The gas law associated with this is Avogadro's law.

Explanation:

Avogadro's law states that the volume of the gas is directly proportional to the number of moles of the gas at constant pressure and temperature

Mathematically,

[tex]V\propto n[/tex]                   (At constant pressure and temperature)

OR

[tex]\frac{V_1}{n_1}=\frac{V_2}{n_2}[/tex]               .....(1)

where,

[tex]V_1\text{ and }n_1[/tex] = Initial volume and number of moles

[tex]V_2\text{ and }n_2[/tex] = Final volume and number of moles

We are given:

[tex]V_2=\frac{V_1}{2}[/tex]

Putting values in equation 1, we get:

[tex]\frac{V_1}{n_1}=\frac{V_1}{2\times n_2}\\\\n_2=\frac{n_1}{2}[/tex]

(a):

If [tex]n_1[/tex] number of moles of gas contains X number of molecules

So, [tex]\frac{n_1}{2}[/tex] number of moles of gas will contain = [tex]\frac{X}{n_1}\times {n_1}{2}=\frac{X}{2}[/tex] number of molecules

Hence, the balloon will contain [tex]\frac{X}{2}[/tex] number of molecules now.

(b): The law used is Avogadro's law.

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