Answer:
[tex]Height = 173.8ft[/tex]
Step-by-step explanation:
Given
[tex]\theta = 40^o[/tex]
[tex]d = 200ft[/tex] --- distance from building
[tex]h=6ft[/tex]--- height of the building
Let the height of the building be H. So:
[tex]\tan(\theta) = \frac{Opposite}{Adjacent}[/tex]
[tex]\tan(40) = \frac{H}{200}[/tex]
Make H the subject
[tex]H = 200 * \tan(40)[/tex]
[tex]H = 167.82[/tex]
The required height s:
[tex]Height = H + h[/tex]
[tex]Height = 167.82 + 6[/tex]
[tex]Height = 173.82ft[/tex]
[tex]Height = 173.8ft[/tex] --- approximately
