What is the final, balanced equation that is formed by combining these two half reactions?
CO
Cu-
> Cu2+
+ 2e-
NO3 + 2e + 2H
>NO2+H20
o Cu2+ + NO3 + + 4e + 2H+ -> Cu + NO3 + H20
o Cu + NO3 + 2H*
>Cu2+ + NO3 + H20
o 2Cu + NO3 + 2H+ —>2Cu?* + NO3 + H20
O Cu+ NO3 + 2H+—
+ NO2 + 2H20

Respuesta :

Answer: Balanced equation that is formed by combining these two half reactions is [tex]Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O[/tex].

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, [tex]Cu \rightarrow Cu^{2+} + 2e^{-}[/tex]

[tex]NO^{-}_{3} + 2e^{-} + 2H^{+} \rightarrow NO^{-}_{2} + H_{2}O[/tex]

On cancelling the common species from both these half-reactions, the complete balanced equation will be as follows.

[tex]Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O[/tex]

Thus, we can conclude that balanced equation that is formed by combining these two half reactions is [tex]Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O[/tex].

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