Therefore, 5000 items can maximize the profit
The correct answer is an option (a)
The money that you make when you sell something for more than it cost you.
For given example,
profit is described by the equation :
[tex]P (x) = -x^2 + 10x -4[/tex]
We need to maximize the profit P(x)
[tex]\Rightarrow \frac{d}{dx}P(x)=0\\\\\Rightarrow \frac{d}{dx}( -x^2 + 10x -4 ) =0\\\\\Rightarrow -2x+10=0\\\\\Rightarrow -2x=-10\\\\\Rightarrow x=5[/tex]
since , x is the number of items made in thousand
Therefore, 5000 items can maximize the profit
The correct answer is an option (a)
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