Answer:
Exact Length = 2*sqrt(30)
Approximate Length = 10.95445
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Work Shown:
(tangent)^2 = (external secant)*(whole secant)
(CD)^2 = (CB)*(CA)
(CD)^2 = (CB)*(CB+BA)
x^2 = 5*(5+19)
x^2 = 120
x = sqrt(120)
x = sqrt(4*30)
x = sqrt(4)*sqrt(30)
x = 2*sqrt(30) .......... exact length
x = 10.95445 ............. approximate length
The length of the tangent segment is; x = 10.95
From secant theorem, we know that;
Tangent ² = length of external secant × total length of secant.
From the image, we see that;
Length of tangent is x.
External secant = 5
Total length of secant = 19 + 5 = 24
Thus;
x² = 5 × 24
x² = 120
x = √120
x ≈ 10.95
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