KUR00
contestada

log (sqrt(xy))/z is equal to

a) 1/2 logx + 1/2 logy - logz
b) 1/2 logx + logy - logz
c) 1/2 (logx + logy - logz)
d) 1/2 log xy/ logz

Respuesta :

Answer:

A) [tex]\frac{1}{2}log(x)+\frac{1}{2}log( y)-log(z)[/tex]

Step-by-step explanation:

[tex]log\frac{\sqrt{xy}}{z}[/tex]

[tex]log\sqrt{xy}-log(z)[/tex]

[tex]log(xy)^\frac{1}{2}-log(z)[/tex]

[tex]\frac{1}{2}log(xy)-log(z)[/tex]

[tex]\frac{1}{2}(log(x)+log(y))-log(z)[/tex]

[tex]\frac{1}{2}log(x)+\frac{1}{2}log( y)-log(z)[/tex]

Therefore, A is correct

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