contestada

Determine the type of inhibition that has occurred in a first order Michaelis-Menten enzyme catalyzed reaction that has yielded the following data. Vi is the velocity in the presence of inhibitor, V is the velocity when run without inhibitor and [S] refers to the substrate concentration. [S] V Vi 3.333 0.283 0.055 1.000 0.260 0.054 0.400 0.222 0.052 0.263 0.197 0.051 0.179 0.171 0.049

Respuesta :

Answer:

competitive inhibition

Explanation:

Given in the first order [tex]\text{Michaelis-Menten enzyme catalyzed reaction}[/tex].

[tex]$V_i$[/tex] = velocity in the presence of the inhibitor

V = velocity when run without the inhibitor.

S = substrate concentration

We need to plot a curve for [tex]$\frac{1}{[V]}$[/tex]  vs  [tex]$\frac{1}{[S]}$[/tex]  and a second plot of  [tex]$\frac{1}{[V_i]}$[/tex]  vs  [tex]$\frac{1}{[S]}$[/tex]

By plotting the curve we see that the slope and the intercept are not the same for the two curves.

And also, the [tex]$V_{max}$[/tex] for the second curve with the inhibitor is lower than the first curve.

Therefore, the inhibition type would be competitive.

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE

Otras preguntas