Answer:
The answer is "0.00088"
Step-by-step explanation:
Many ways of selecting r articles of n,[tex]\to ^nC_r = \frac{n!}{(r! \times (n-r)!)}[/tex]
P(wins the player) = [tex]\frac{1}{\text{Any combinations of possible numbers}}[/tex]
[tex]= \frac{1}{^{20} C_3}\\\\[/tex]
[tex]= \frac{1}{\frac{20!}{(3!\times 17!)}}\\\\= \frac{1}{1140}\\\\= 0.00088[/tex]
