Answer:
(a) a ≈ 22.7 meters, (b) c ≈ 10.6 meters, (c) ∠A = 65°
Step-by-step explanation:
assuming side a/c is side BC/AB since it's opposite of angle A/C
(a) SOH CAH(cos = adjacent side/hypotenuse) TOA
=> cos (25°) = BC/AC or a/b
=> cos (25°) = a/25
=> a = cos (25°) × 25
=> a ≈ 22.7
(b) SOH(sin = opposite side/hypotenuse) CAH TOA
=> sin (25°) = AB/AC or c/b
=> sin (25°) = c/25
=> c = sin (25°) × 25
=> c ≈ 10.6
(c) 180° - 25° - 90°(the right angle) = 65°
