If one-sixth of a certain number is four more than one-twelfth the number, the required number will be 48.
Let the unknown number be 'a'
One-sixth of the number is expressed as 1/6 a ..... 1
One-twelfth the number is also expressed as 1/12 a
Four more than one-twelfth the number will be written as:
1/12 a + 4 .... 2
Equating 1 and 2 will give:
1/6 a = 1/12 a + 4
a/6 = a/12 + 4
Collect the like terms
[tex]\frac{a}{6} - \frac{a}{12} = 4[/tex]
Find the LCM
[tex]\frac{2a-a}{12} = 4\\\frac{a}{12} = 4[/tex]
Cross multiply
a = 12×4
a = 48
This shows that the required number is 48
Learn more on equations here: https://brainly.com/question/14034270
