Given:
The line passes through the two points (–4, –3) and (12, 1).
The point-slope form of the equation of the line is:
[tex]y-1=\dfrac{1}{4}(x-12)[/tex]
To find:
The standard form of the equation for this line.
Solution:
The standard form of a line:
[tex]Ax+By=C[/tex]
The given point-slope form of the equation of the line is:
[tex]y-1=\dfrac{1}{4}(x-12)[/tex]
Multiply both sides by 4.
[tex]4(y-1)=(x-12)[/tex]
[tex]4y-4=x-12[/tex]
[tex]-4+12=x-4y[/tex]
[tex]8=x-4y[/tex]
Interchanging the sides, we get
[tex]x-4y=8[/tex]
Therefore, the standard form of the equation for this line is [tex]x-4y=8[/tex].
