Helena has a set of number cards numbered 1 thru 10. If Helena randomly draws two cards from the deck, what is the probability that she will draw an odd number and then a two?

A. 6/10
B. 5/10
C. 1/9
D. 5/90

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Anonymous123456677 Anonymous123456677 · Answer 1 · 2021-05-20T20:42:06+02:00

Answer:

5/90

Step-by-step explanation:

There are 5 odd numbers out of 10

We can use a fraction 5/10

Then we multiply it by 1/9

Because there is only 1 card numbered two in the 9 cards left.

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varshamittal029 varshamittal029 · Answer 2 · 2022-07-08T12:08:14+02:00

The probability that Helena will draw an odd number and then a two is given by (D) 5/90.

Probability is the possibility of occurence of an event.

In mathematical words, it is ratio of number of favorable case to the total number of cases.

Probability = (Number of Favorable Cases)/(Number of Total Cases)

Now there are 5 odd numbers and 5 even numbers in 1 ro 10.

So favorable case to choose an odd number from 1 to 10 is 5

So the probability to choose odd number from 10 cards = 5/10

Now after choosing one odd total number of card is 9 and there is 4 odd and 5 even cards.

but there is only one 2 numbered card.

So probability to choose a two from rest 9 cards = 1/9

Hence the required probability to draw an odd number and then a two is = (5/10)*(1/9) = (5*1)/(10*9) = 5/90

Hence correct option is (D).

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