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A line passes through the points (3, 9) and (0, 3). What is its equation in slope-intercept form?

Write your answer using integers, proper fractions, and improper fractions in simplest form.

Respuesta :

Answer:

[tex] y = 2x + 3 [/tex]

Step-by-step explanation:

Given :-

  • Two points are given to us .
  • The points are (3,9) and (0,3) .

And we need to find the equation in slope intercept form. So here we can find the equation of the line using two point form , as ,

[tex]\implies y - y_1 = \dfrac{ y_2-y_1}{x_2-x_1}( x - x_1) [/tex]

  • Now plug in the respective values ,

[tex]\implies y - 9 = \dfrac{ 3-9}{0-3}( x - 3) \\\\\implies y - 9 =\dfrac{-6}{-3}( x - 3 ) \\\\\implies y - 9 = 2( x - 3 ) \\\\\implies y - 9 = 2x - 6 \\\\\implies y = 2x - 6 +9 \\\\\implies \boxed{ y = 2x + 3 }[/tex]

Hence the equation in slope intercept form is y = 2x + 3.

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