Respuesta :
Answer:
B. By = 0.067 × 10-8cos[(0.63 m-1)z + (1.9 × 108 s-1)t] T.
Explanation:
Since the electric field has a maximum at x = 0 and t = 0, it is a cosine function and thus the magnetic field is also a cosine function.
Also, the electric field travels in the x - direction and the wave in the z-direction. Since the magnetic field is perpendicular to both directions, it must thus move in the y - direction.
So, By = B₀cos(kz - ωt). It has a negative sign since the wave is travelling in the positive z - direction.
Since c = E₀/B₀ where E₀ = amplitude of electric field = 0.20 V/m, B₀ = amplitude of magnetic field and c = speed of light = 3 × 10⁸ m/s
So, B₀ = E₀/c = 0.20 V/m ÷ 3 × 10⁸ m/s = 0.067 × 10⁻⁸ T
wave number, k = 2π/λ where λ = wavelength = 10 m. So, k = 2π/10 m = 6.28/10 m = 0.628 m⁻¹ ≅ 0.63 m⁻¹
angular frequency, ω = 2πf where f = frequency of wave = c/λ = 3 × 10⁸ m/s 10 m = 3 × 10⁷ s⁻¹. So, ω = 2πf = 2π(3 × 10⁷ s⁻¹) = 18.8 × 10⁷ s⁻¹ = 1.88 × 10⁸ s⁻¹ ≅ 1.9 × 10⁸ s⁻¹
Substituting the variables into By, we have
By = B₀cos(kz - ωt)
By = (0.067 × 10⁻⁸ T)cos[(0.63 m⁻¹)z - (1.9 × 10⁸ s⁻¹)t]
By = 0.067 × 10⁻⁸cos[(0.63 m⁻¹)z - (1.9 × 10⁸ s⁻¹)t] T
Since none of our options contain the given answer, we assume the wave moves in the negative z - direction. So, for that,
By = 0.067 × 10⁻⁸cos[(0.63 m⁻¹)z + (1.9 × 10⁸ s⁻¹)t] T
Answer:
D.
[tex]\mathbf{B_y = 0.067 \times 10^{-8} Cos \Big[ 0.6 3m^{-1} z - (1.9 \times 10^{-6} \ s^{-1})t \Big] T}[/tex]
Explanation:
From the given information:
Let us recall that the direction with which electromagnetic wave proceeds is usually along [tex]E^{ \to} \times B^{\to}[/tex]
Thus; the magnetic field is always along the y-direction.
In the magnetic field, the maximum value of the field is expressed by using the formula:
[tex]\dfrac{E}{C} = \dfrac{0.20 \ V/m}{3\times 110^8 \ m/s} \\ \\ = 0.067 \times 10^{-8} \ T[/tex]
Given that:
the maximum x is starting at 0, then, it implies that it is starting from the extreme position proceeding along +z direction.
As such; the general equation: [tex]y = A sin (\omega t - kz)[/tex]
Also:
[tex]K = \dfrac{2 \pi}{\lambda}[/tex]
where;
[tex]\lambda =10[/tex]
[tex]K = \dfrac{2 \pi}{10}[/tex]
K ≅ 0.63 m⁻¹
Thus;
[tex]\mathbf{B_y = 0.067 \times 10^{-8} Cos \Big[ 0.6 3m^{-1} z - (1.9 \times 10^{-6} \ s^{-1})t \Big] T}[/tex]