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20-05-2021
Mathematics

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How many moles are there in 993.6 grams of potassium sulfate (K2SO4)?

Respuesta :

23-05-2021

Answer:

Solution given:

K₂SO₄➙1mole

K₂SO₄➙39*2+32+16*4=174g

we have

174g➙1mole

993.6g➙[tex] \frac{993.6}{174} [/tex]=5.7mole

5.7moles are there in 993.6 grams of potassium sulfate (K2SO4).

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